Odd and Even Numbers Program in C

In this program, we will check whether the number entered by the user is odd or even. First, we make a C program to check whether the number is odd or even using the if-else statement and in another program, we use a switch-case statement.

Approach to make Odd and even numbers program in c:

• First, we initialize a number using the int data type.
• We take the value of our num identifier by the user.
• We use the below if-else statement to check whether the number is odd or even

C program to check whether the number is odd or even using an if-else statement

#include<stdio.h>
int main()
{
    int num;
    printf("Enter a number:");
    scanf("%d",&num);
    if(num%2==0)
        printf("%d is an even number.",num);
    else    
        printf("%d is an odd number.",num);
    return 0;
}

Output:-
Enter a number:4
4 is even_

The if-else format in the Odd and even numbers program in c program

if(condition) //condition is num%2==0
Statement 1;
else
Statement 2;
If the condition is true then statement 1 is executed.
if the condition is not true then statement 2 is executed.

Check whether a number is odd or even using bitwise operators

In odd numbers, the bit furthest to the right is 1. So, if we perform "&" operation between number and 1 then we will get one. For example, The binary representation of 3 is 011. 011 &001 is 1.

z=N & 1
if z is 0, then N is an even number
if z is 1, then N is an odd number

#include<stdio.h>

int main()
{
    int num;
    printf("Enter a number:");
    scanf("%d",&num);
    if(num&1)
        printf("%d is odd",num);
    else    
        printf("%d is even",num);
    return 0;
}

C program to check whether the number is odd or even using a switch-case statement

#include<stdio.h>

int main()
{
    int num;
    printf("Enter a number:");
    scanf("%d",&num);
    switch(num%2)
    {
        case 0:printf("%d is even",num);
                break;  
        case 1:printf("%d is odd",num);
    }
    return 0;
}

Output:
Enter a number:7
7 is odd_

FAQ on Odd and even numbers program in c

1. How do you program odd and even numbers?
Even numbers are divisible by 2 means if even numbers are divided by 2 gives a remainder of 0. Odd numbers are not divisible by 2 means if odd numbers are divided by 2 gives a remainder of 1. When a number is divided by 2, we check the remainder using the modulus operator which is denoted by “%”.

 For example num%2 (num can be any natural number)

2. How do you write a c program even or odd?
Odd and even numbers program in c #include<stdio.h>
int main()
{
int a;
printf("Enter any number:");
scanf("%d",&a);
if(a%2==0)
printf("%d is an even number",a);
else
printf("%d is an odd number",a);
return 0;
}

3.How do I make an even odd program in c++? 

#include<iostream.h>
int main()
{
int a;
cout<<"\n Enter any number:";
cin>>a;
if(a%2==0)
cout<<a<<" is an even number";
else
cout<<a<<" is an odd number";
return 0;
}

About this program
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